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10-6v^2=-374
We move all terms to the left:
10-6v^2-(-374)=0
We add all the numbers together, and all the variables
-6v^2+384=0
a = -6; b = 0; c = +384;
Δ = b2-4ac
Δ = 02-4·(-6)·384
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-6}=\frac{-96}{-12} =+8 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-6}=\frac{96}{-12} =-8 $
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